3.2.59. VERIFY(string,ref[,[option][,start]])

With only the first two parameters, it will return the position of
the first character in string that is not also a character in the
string ref. If all characters in string are also in ref, it will
return 0.

If option is specified, it can be one of:

[N]
     (Nomatch) The result will be the position of the first
     character in string that does exist in ref, or zero if all
     exist in ref. This is the default option.

[M]
     (Match) Reverses the search, and returns the position of the
     first character in string that exists in ref. If none exists
     in ref, zero is returned.

If start (which must be a positive whole number) is specified, the
search will start at that position in string. The default value
for start is 1.

     VERIFY(‘foobar’, ‘barfo’)          –>   ‘2’
     VERIFY(‘foobar’, ‘barfo’, ‘M’)     –>   ‘2’
     VERIFY(‘foobar’, ‘fob’, ‘N’)       –>   ‘5’
     VERIFY(‘foobar’, ‘barf’, ‘N’, 3)   –>   ‘3’
     VERIFY(‘foobar’, ‘barf’, ‘N’, 4)   –>   ‘0’


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